Sort dictionary by key and value
people = {3: "Jim", 2: "Jack", 4: "Jane", 1: "Jill"}
key_sorted = dict(sorted(people.items()))
print(f"{key_sorted = }")
value_sorted = dict(sorted(people.items(), key=lambda item: item[1]))
print(f"{value_sorted = }")
Output
Sort a list of dictionaries
The next set of everyday list tasks is sorting. Depending on the data type of the items included in the lists, we’ll follow a slightly different way to sort them. Let’s first start with sorting a list of dictionaries.
dicts_lists = [
{
"Name": "James",
"Age": 20,
},
{
"Name": "May",
"Age": 14,
},
{
"Name": "Katy",
"Age": 23,
},
]
# There are different ways to sort that list
# 1 - Using the sort/ sorted function based on the name or age
dicts_lists.sort(key=lambda item: item.get("Name"))
print(dicts_lists)
dicts_lists.sort(key=lambda item: item.get("Age"))
print(dicts_lists)
# 2 - Using itemgetter module based on name
from operator import itemgetter
f = itemgetter("Name")
dicts_lists.sort(key=f)
print(dicts_lists)
Output
Sort a list based on another list
Sometimes, we may want or need to use one list to sort another. So, we’ll have a list of numbers (the indexes) and a list that I want to sort using these indexes
a = ['blue', 'green', 'orange', 'purple', 'yellow']
b = [3, 2, 5, 4, 1]
#Use list comprehensions to sort these lists
sortedList = [val for (_, val) in sorted(zip(b, a), key=lambda x: x[0])]
Output